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Re: [Xen-users] Both Dom0 and DomU have the same ip address...
- To: trist007 <drakoth777@xxxxxxxxx>
- From: "Brian Stempin" <brian.stempin@xxxxxxxxx>
- Date: Sun, 13 Apr 2008 21:53:34 -0400
- Cc: xen-users@xxxxxxxxxxxxxxxxxxx
- Delivery-date: Sun, 13 Apr 2008 18:54:09 -0700
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Ooops...forgot to post to the list....
route -n will not show your IP address.
Try using ifconfig to obtain that information.
On Sun, Apr 13, 2008 at 9:57 AM, trist007 < drakoth777@xxxxxxxxx> wrote:
How do I assign a public ip address for Dom0 and then a separate one for
DomU? I wanna do this so I can get some practice using ssh from dom0 to
DomU. I wanted to interact between the two to get some good networking
experience using all sorts of protocols between the two. Anyhow, I have
eth0 on dom0 as dhcp. So when peth0 comes up during the network-bridge
script, which then turns into eth0 on domU it comes out as having the same
ip address. Then again I might be confused. I have a router which has the
default gateway of 192.168.1.1 so I know that's where dom0 and domU hook up
to the internet. So here is my confusion. I've been using
www.whatismyip.com to find out my ipaddress. I know this is the external ip
address. Also, I've been using route -n to get dom0 and domU's internal ip
address. That address would be the 1st ip address from the output in route
-n? If that's true, they're both 198.168.1.0 But since this external ip
address is the same for both dom0 and domU, would this be the external ip
address of the router? I guess for now, I could be using internal ips to
interact between dom0 and domU but I wanted to be able to do both. I'd like
to interact with domU using dom0 via external ip and internal ip so I could
get all the experience.
So what should I do? I'm guessing I need to make a static ip for eth0 on
dom0, but if I did this, wouldn't eth0 on domU be the same address? Or do I
need to do some port forwarding, one to dom0 and one to domU, but how can I
if they both have the same internal ips. I've been reading up different
guides online, but for some reason I can understand this section of
networking. Could somebody please explain this.
--
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