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Re: [PATCH v2 4/4] pcmcia: Convert to use pci_bus_for_each_resource_p()



Am Thu, Nov 03, 2022 at 06:46:44PM +0200 schrieb Andy Shevchenko:
> The pci_bus_for_each_resource_p() hides the iterator loop since
> it may be not used otherwise. With this, we may drop that iterator
> variable definition.

Thanks for your patch!

> diff --git a/drivers/pcmcia/rsrc_nonstatic.c b/drivers/pcmcia/rsrc_nonstatic.c
> index ad1141fddb4c..9d92d4bb6239 100644
> --- a/drivers/pcmcia/rsrc_nonstatic.c
> +++ b/drivers/pcmcia/rsrc_nonstatic.c
> @@ -934,7 +934,7 @@ static int adjust_io(struct pcmcia_socket *s, unsigned 
> int action, unsigned long
>  static int nonstatic_autoadd_resources(struct pcmcia_socket *s)
>  {
>       struct resource *res;
> -     int i, done = 0;
> +     int done = 0;
>  
>       if (!s->cb_dev || !s->cb_dev->bus)
>               return -ENODEV;
> @@ -960,12 +960,9 @@ static int nonstatic_autoadd_resources(struct 
> pcmcia_socket *s)
>        */
>       if (s->cb_dev->bus->number == 0)
>               return -EINVAL;
> -
> -     for (i = 0; i < PCI_BRIDGE_RESOURCE_NUM; i++) {
> -             res = s->cb_dev->bus->resource[i];
> -#else
> -     pci_bus_for_each_resource(s->cb_dev->bus, res, i) {
>  #endif
> +
> +     pci_bus_for_each_resource_p(s->cb_dev->bus, res) {
>               if (!res)
>                       continue;

Doesn't this remove the proper iterator for X86? Even if that is the right
thing to do, it needs an explict explanation.

>  
> diff --git a/drivers/pcmcia/yenta_socket.c b/drivers/pcmcia/yenta_socket.c
> index 3966a6ceb1ac..b200f2b99a7a 100644
> --- a/drivers/pcmcia/yenta_socket.c
> +++ b/drivers/pcmcia/yenta_socket.c
> @@ -673,9 +673,8 @@ static int yenta_search_res(struct yenta_socket *socket, 
> struct resource *res,
>                           u32 min)
>  {
>       struct resource *root;
> -     int i;
>  
> -     pci_bus_for_each_resource(socket->dev->bus, root, i) {
> +     pci_bus_for_each_resource_p(socket->dev->bus, root) {
>               if (!root)
>                       continue;
>  

That looks fine!

Thanks,
        Dominik



 


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